I want only short method. long method like divide and then check the reminder is not allowed
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To make given number divisible by 33, it must be divisible by both 3 and 11.
Checking with 3:
2 + 3 + 1 + 2 + 2 + 8 = 18
Therefore now it is divisible by 3.
Checking with 11:
2 + 1 + 2 = 5
8 + 2 + 3 = 13
Difference: 13 - 5 = 8
For the number to be divisible by 11, difference must be 0 or a multiple of 11.
For the number to be divisible by 33, it should also be divisible by 3 (sum of digits should be a multiple of 3).
Adding 3 in units place satisfies both the conditions.
Hence, answer is 3.
Thanks, kindly mark as brainliest if you are satisfied with the answer.
Checking with 3:
2 + 3 + 1 + 2 + 2 + 8 = 18
Therefore now it is divisible by 3.
Checking with 11:
2 + 1 + 2 = 5
8 + 2 + 3 = 13
Difference: 13 - 5 = 8
For the number to be divisible by 11, difference must be 0 or a multiple of 11.
For the number to be divisible by 33, it should also be divisible by 3 (sum of digits should be a multiple of 3).
Adding 3 in units place satisfies both the conditions.
Hence, answer is 3.
Thanks, kindly mark as brainliest if you are satisfied with the answer.
abhishek2984:
thanks this is exactly what I wanted
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