Math, asked by abhishek2984, 1 year ago

I want only short method. long method like divide and then check the reminder is not allowed

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Answered by artyaastha
3
To make given number divisible by 33, it must be divisible by both 3 and 11.

Checking with 3:

2 + 3 + 1 + 2 + 2 + 8 = 18
Therefore now it is divisible by 3.

Checking with 11:

2 + 1 + 2 = 5
8 + 2 + 3 = 13
Difference: 13 - 5 = 8

For the number to be divisible by 11, difference must be 0 or a multiple of 11.

For the number to be divisible by 33, it should also be divisible by 3 (sum of digits should be a multiple of 3).

Adding 3 in units place satisfies both the conditions.

Hence, answer is 3.

Thanks, kindly mark as brainliest if you are satisfied with the answer.

abhishek2984: thanks this is exactly what I wanted
artyaastha: Thanks! Actually I had got a call. That is why there was along gap in between.
abhishek2984: oh that's totally cool , no issue for that
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