Question

i want question 4full Solution please...

#java..


it's model paper...2019​

Answer 1

$\bold{QUESTION \: 4}$

a) -ADVANTAGES OF AR RAY

▶Array can store multiple values of same data types at a same time .

▶They values stored in an array can be invoked any time by a for or while loop.

▶Data stored can easy be arranged into its decreasing and increasing order

▶Values can be invoked anywhere and can be compared or can be changed.

b) -LINEAR SEARCH

▶It will work for both sorted and unsorted data .

▶The search begins by comparing that particular value to all the values in the array from starting.

BINARY SEARCH

▶It works only for sorted data, whether ascending or descending.

▶In this array is divided into two parts and then value is searched depending on the value is greater or smaller .

c) -

T=0

I=1

T=2

I=3

L=4

I=5

=6

A=7

T=8

T=9

A=10

C=11

K=12

E=13

D=14

=15

O=16

N=17

=18

1=19

1=20

T=21

H =22

=23

O=24

C=25

T=26

O=27

B=28

E=29

R=30

▶i= 26

Character . toLowerCase(str . CharAt(i))

Character . toLowerCase(str . CharAt(26))

t

▶i=26-6=20

Character . toLowerCase(str . CharAt(i))

Character . toLowerCase(str . CharAt(20))

t

▶i=20-6=14

Character . toLowerCase(str . CharAt(i))

Character . toLowerCase(str . CharAt(d
14))

d


▶i=14-6=8

Character . toLowerCase(str . CharAt())

Character . toLowerCase(str . CharAt(8))

t

▶i=8-6=2

Character . toLowerCase(str . CharAt(i))

Character . toLowerCase(str . CharAt(2))

t

▶i=2 - 6= -4

Loop will execute but will not print the value.

$\boxed{O U T P U T}$

$\boxed{t1dtt}$

d) - Two jump statements are

▶Break

▶Continue

e) a = -9.5

Math . round prints the round off= -9.0

Math . rint prints the round off= -9.0

$\boxed{O U T P U T}$

Rounded value =-9.0

Rinted value = -9