I want question no 32
33
And
34 also plss urgent I need it plsss
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33-Potassium nitrate
--hydrochloric acid
--calcium chloride
-- calcium carbonate
Valency of X -- 4
--electronic conifiguration --2,8,4
--hydrochloric acid
--calcium chloride
-- calcium carbonate
Valency of X -- 4
--electronic conifiguration --2,8,4
Answered by
1
Question No.32
56g of Na atoms
Number of fundamental particles = No.of moles * 6.022*10^23
--> No.of moles = Given mass/Atomic Mass
--> No.of moles = 56/23 = 2.44
Therefore, Number of particles of Na
= 2.44*6.022*10^23
=14.4*10^23 (Ans)
Question No.33
Pretty Direct;
a].KNO3 -->> Potassium Nitrate
b]HCl -->> Hydrogen Chloride
C] CaCl2 --> Calcium Chloride
D] CaCO3 --> Calcium Carbonate
Question 34.
No.of protons and Electrons are 14
Valency is 4
Electronic config.
2,8,4
or
1s2 2s2 2s2 2p6 3s2
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