Question

(I want saishree to answer )
insert 4 arithmetic means between 3 and 38

Answer 1

Apologies.
Back to the question.

Let the common difference of the numbers inserted within be d.

Now,
We already have the first term (a) as 3 and last term as (z) as 38 counting other four numbers we just inserted we have a total of 6 numbers here.

So the A.P series will look something like,

3, (3+d), (3+2d) ,(3+3d), (3+4d), 38.

Since the common difference is d and the last term will be the 6th term,

We have,

$38 = a + 5d \\ 38 = 3 + 5d \\ 35 = 5d \\ \\ d = 7$

We will use this value in the inserted numbers.

So the four numbers inserted will be,

(3+7),(3+14),(3+21),(3+28)

= 10, 17, 24, 31

Answer 2

10,17,23,30

Step-by-step explanation:

Common difference 7

total numbers 6 including starting and ending.

start 3 end 38

as per formula

38 = 3 + 5d

d= common difference

which we have to find

so d will be 7

now add it from start 3+7, 3+2d means 3+14 like wise.

so you will get full series 3,10,17,23,30 & 38

thank you