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distance between (tan ,2) ( 0,1)
√ (1-2)^2 + (0 - tan)^2
√ 1 + tan^2
√ sec^2
As we know in 90 to 180 interval, sec is negative
And √ sec^2 will always give positive no
so it's - sec a
(4) option
√ (1-2)^2 + (0 - tan)^2
√ 1 + tan^2
√ sec^2
As we know in 90 to 180 interval, sec is negative
And √ sec^2 will always give positive no
so it's - sec a
(4) option
thanq so much
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