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angle A = angle C [opposite angles of parallelogram]
= 1/2 angle A= 1/2 angle C = angle XAY = angle YCD..... eqn 1
,,, now, DC parallel to AB and CY is transversal.
= angle YCD= angle CYB .............. eqn 2 [alternate interior angles]
from eqn 1 and 2 we get..
angle XAB = angle CYB
but , these are corresponding angles formed of a parallelogram when AX and CY are Cut transversal AB.
:. AX parallel to CY..
proved..
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