Question

(I WANT STEP BY STEP EXPLANATION)My age is a 2-digit number. when my age is multiplied by 9, I get a 3-digit number. If the digit 4 is written before the 3-digit number and the digit 6 is written after the 3-digit number, I get a 5-digit number which is greater than the 3-digit number by 42355. How old am I? ​
(I WANT STEP BY STEP EXPLANATION)​

Answer 1

Answer:

Please check the attachment

Step-by-step explanation:

this is a tricky one

Answer 2

Answer :- 29 years

$\bf\huge\underline{\underline{ Given :- }}$

• age is 2 digit number

• when multiplied by 9 gives 3 digit number

• when 4 and 6 are added to front and back gives 3 digit number greater than 42355.

$\bf\huge\underline{\underline{ To \: Find:- }}$

• Find the age

$\bf\huge\underline{\underline{ Answer :- }}$

Let the digits be x and y

• 2 digit number = 10x + y

• 9 ( 10x + y) $\red{\implies}$ 100a + 10b + c

• 40000 + (100a + 10b + c )10 + 6 $\red{\implies}$ 42355 + 100a + 10b + c

• 40000 - 40000 + (10-1)(100a+10b+c) = 2355-6

• 9(100a+10b+c) = 2349

• 100a+10b+c =$\frac{2349}{9}$

• 100a + 10b + c = 261

• 10x + y = $\frac{(100a+10b+c)}{9}$

• 10x + y = $\frac{261}{9}$

• 10x + y = 29