Question

I WANT THAT question ANSWER​

Answer 1

Answer:

that is solved by identities....

Answer 2

Answer:

We have,

${t}^{2} - 2t + 1$

We now that,

${a}^{2} - 2ab + {b}^{2} = {(a - b)}^{2}$

Here a = t and b = 1

$Therefore \: {t}^{2} - 2t + 1 = {(t)}^{2} - 2(t)(1) + {1}^{2}$

$= {(t - 1)}^{2}$

$= (t - 1)(t - 1)$