I want the answer of 3,4,5
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area of equilateral triangle= 9√3cm^2. Area = √3a^2/4 where=6cm
MANKOTIA:
Area of isosceles triangle = 12cm^2
qn,5,) ans .Area=bh/2 =4×3/2=6cm^2
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5. Height = √ (5)^2 - (4)^2
= √25-16
= √9
= 3cm
Now, Area of triangle = 1/2*base*height
=1/2*4*3
=6cm^2
3. Altitude of isosceles triangle = √a^2 - b^2/4
= √5^2-6^2/4
=√25-36/4
=√25-9
=√16
= 4cm
Now, Area of isosceles triangle = b*h/2
=6*4/2
=24/2
=12 cm^2
= √25-16
= √9
= 3cm
Now, Area of triangle = 1/2*base*height
=1/2*4*3
=6cm^2
3. Altitude of isosceles triangle = √a^2 - b^2/4
= √5^2-6^2/4
=√25-36/4
=√25-9
=√16
= 4cm
Now, Area of isosceles triangle = b*h/2
=6*4/2
=24/2
=12 cm^2
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