Question

i want the answer of any one question.....pls quick​

Answer 1

Step-by-step explanation:

hello u can answer any one you want

Answer 2

(iii)p (x)=kx^2-root2x+1

=×-1

zeros of the polynomial

=x-1=0

x=1

p(x)=k(x)^2-root2x+1=0

=k(1)^2-root2(1)+1=0

=k-root 2+1=0

=k=-1+root2 answer