Question

i want the answer of third question​

Answer 1

Steps for construction:
Step 1 : Draw a rough diagram and mark the given measurements. Draw
CE
∥
DA
. Now AECD is a parallelogram. ∴ EC = 5 cm, AE = DC = 4 cm, EB = 3cm.

Step 2 : Draw a line segment AB = 7 cm.

Step 3 : Mark E on
AB
such that AE = 4 cm . [ ∵ DC = 4 cm ]

Step 4 : With B and E as centres draw two arcs of radius 5 cm and let them cut at C.

Step 5 : With B as centre and radius 6 cm draw an arc cutting
BY
at C.

Step 6 : With C and A as centres and with 4 cm and 5 cm as radii draw two arcs. Let them cut at D.

Step 7 : Join
AD
and
CD
. ABCD is the required trapezium.

Step 8 : From D draw
DF
⊥
AB
and measure the length of DF. DF = h = 4.8 cm, AB = a = 7 cm, CD = b = 4 cm.

Calculation of area:In the trapezium ABCD, a = 7 cm, b = 4 cm and h = 4.8 cm.

Area of the trapezium ABCD =
2
1
​
h(a+b)

=
2
1
​
(4.8)(7+4)

=
2
1
​
× 4.8 × 11

= × 2.4 × 11
=26.4 cm
2