Question

I want the answer please ​

Answer 1

Step-by-step explanation:

$\int \frac{dy}{dx} = \int(8 {x}^{3} - 4x + 1 )$

$y = 8 \frac{ {x}^{4} }{4} - 4 \frac{ {x}^{2} }{2}+ x$

$y = 2 {x}^{4} - 2 {x}^{2} + x$

at y(1)=3

$y = 2. {1}^{4} - 2 .{1}^{2} + 1 = 2 - 2 + 1 = 1$