Question

i want the answer pls. ​

Answer 1

Answer:

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Explanation:

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Answer 2

Al2O3 ionises as,

Al2O3⇌ Al3+Cathode+AlO3−Anode

At cathode

Al3++3e−3F→Al27g

∵ Mass of aluminium deposited by 3 F of electricity = 27 g

∴ Mass of aluminium deposited by

4.0×104×6×3600Cofelectricity

=27×4.0×104×6×36003Fg

=27×4.0×104×6×36003×96500g

=8.1×104g