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Answers
Answer:
Answer:
Given :-
The point of 20 MJ work is done in moving a change of 100 uc across two points in an electric circuit.
To Find :-
What is the potential difference between the two points.
Formula Used :-
\clubsuit♣ Potential Difference Formula :
\begin{gathered}\mapsto \sf\boxed{\bold{\pink{V =\: \dfrac{W}{Q}}}}\\\end{gathered}
↦
V=
Q
W
where,
V = Potential Difference
W = Work Done
Q = Charge
Solution :-
First, we have to change work done MJ to J :
\implies \sf Work\: Done =\: 20\: MJ⟹WorkDone=20MJ
\begin{gathered}\implies \sf Work\: Done =\: 20 \times 1000000\: J\: \: \small\bigg\lgroup \sf\bold{\pink{1\: MJ =\: 10^6\: or\: 1000000\: J}}\bigg\rgroup\\\end{gathered}
⟹WorkDone=20×1000000J
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1MJ=10
6
or1000000J
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\begin{gathered}\implies \sf Work\: Done =\: 20000000\: J\\\end{gathered}
⟹WorkDone=20000000J
\implies \sf \bold{\purple{Work\: Done =\: 2 \times 10^7\: J}}⟹WorkDone=2×10
7
J
Again, we have to change charge uc to C :
\implies \sf Charge =\: 100\: uc⟹Charge=100uc
\begin{gathered}\implies \sf Charge =\: 100 \times 0.000001\: C\: \small\bigg\lgroup \sf\bold{\pink{1\: uc =\: 0.000001\: or\: 10^{- 6}\: C}}\bigg\rgroup\\\end{gathered}
⟹Charge=100×0.000001C
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1uc=0.000001or10
−6
C
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\implies \sf Charge =\: 0.0001\: C⟹Charge=0.0001C
\implies \sf\bold{\purple{ Charge =\: 10^{- 4}\: C}}⟹Charge=10
−4
C
Now, we have to find the potential difference :
Given :
Work Done (W) = 2 × 10⁷ J
Charge (Q) = 10-⁴ C
According to the question by using the formula we get,
\longrightarrow \sf V =\: \dfrac{2 \times 10^7}{10^{- 4}}⟶V=
10
−4
2×10
7
\longrightarrow \sf V =\: 2 \times 10^3⟶V=2×10
3
\longrightarrow \sf\bold{\red{V =\: 2000\: V}}⟶V=2000V
{\small{\bold{\underline{\therefore\: The\: potential\: difference\: between\: the\: points\: is\: 2000\: V\: .}}}}
∴Thepotentialdifferencebetweenthepointsis2000V.