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Given- In triangle.ABC, altitudes AD and CE intersect each other at P.
To Prove- trAEP ~ trCDP
Proof- In trAEP & trCDP
angleE = angleD = 90*
angleAEP = angleCDP = (v.o.a.)
Therefore
triangleAEP ~ triangleCDP
by (A.A Similarity)
Thanks.....
To Prove- trAEP ~ trCDP
Proof- In trAEP & trCDP
angleE = angleD = 90*
angleAEP = angleCDP = (v.o.a.)
Therefore
triangleAEP ~ triangleCDP
by (A.A Similarity)
Thanks.....
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