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Step-by-step explanation:
in triangle ABC
area of ΔABC = (1/2)*base*height
in first case lets take AB as base then the height will be the perpendicular on AB That is, CF
so area of triangle ABC =(1/2)*AB*CF ..........................(1)
In case second let's take AC as base then the height will be BE
So area of triangle ABC =(1/2)*AC*BE ..............(2)
Since in both cases area of the same triangle ABC is calculated
and BE =CF (Given)
(1/2)*AC*BE = (1/2)*AB*CF
AC=AB
Hence Proved
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