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Angle ABC is equal to Angle BAC
So 50 = 2x + 20
2x = 30
X = 15 °
O is the center of the circle. If ∠BAC=50
∘
, find ∠OBC
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Solution
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Given a circle with it's center at O
∠BAC=50
∘
∠BOC=2∠BAC (Angle made by a chord at centre is twice of angle it makes with circumference.)
=2(50
∘
)
=100
∘
In △OBC,OB=OC=radius
⇒∠OBC=∠OCB ( opposite angles of equal sides of a △ )
Sum of angles in a triangle = 180
∘
∠OBC+∠OCB+∠BOC=180
∘
....(1)
Let∠OBC=∠OCB=x
⟹x+x+∠BOC=180
∘
From (1)
2x=180
∘
−100
∘
=80
∘
⟹x=40
∘
∴∠OBC=x=40
∘
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SIMILAR QUESTIONS
star-struck
Prove that the angle subtended at the centre of a circle is bisected by the radius passing through the mid-point of the arc.
Medium
Two chords AB and AC of a circle subtends angles equal to 90
o
and 150
o
, respectively at the centre. Find ∠BAC, if AB and AC lie on the opposite sides of the centre.