Question

i want the answer with explanation plzzz it's urgent.... ​

Answer 1

Answer:

-1/3

Step-by-step explanation:

tan²30°sin30°+cos60°sin²90°tan²60°-2tan45cos²0sin90

$=(\frac{1}{\sqrt{3}})^2 \frac{1}{2}+ \frac{1}{2}(1)^2(\sqrt3)^2-2(1)(1)^2(1)$

$=\frac{1}{3} \frac{1}{2}+ \frac{1}{2}(1)(3)-2$

$=\frac{1}{6} + \frac{3}{2}-2$

$=\frac{10}{6} -2$

$=-\frac{1}{3}$

Answer 2

-1/3

Step-by-step explanation:

• tan30=1/root3
• sin30=1/2
• cos60=1/2
• sin90=1
• tan60=root3
• tan45=1
• cos0=1
• sin90=1

substitute these values,

(1/root3)2*1/2 + 1/2*(1)2* (root3)2 - 2*1* (1)2* 1

=1/3*1/2 + 1/2*3 - 2

=1/6 + 3/2 - 2

=1/6 + 9/6 - 2

= 10/6 - 2

= 5/3 - 2

= 5-6/3

= -1/3