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Let α, β, Δ be the roots of given polynomial x3-5x2-16x+80.
Given 2 of its roots are equal but of opposite signs
Let α,β be equal roots
such that β = -α
From this polynomial,
Sum of the roots ⇒ α+β+Δ = -coefficient of x²/ coefficient of x³
⇒ α-α+Δ = -(-5)/1
Δ = 5 --------- One of the root (1)
Product of roots ⇒ αβΔ = -constant/coefficient of x³
⇒ α(-α)Δ = -80/1
⇒ -α²Δ = -80
⇒ α²Δ = 80
From(1), Substituting Δ=5
⇒ α²×5 = 80
⇒ α² = 80/5
⇒ α² = 16
⇒ α = √16 = +-4
⇒ α = +4 or -4 {where -4 = -α = β}
Therefore, the three roots of given polynomial x3-5x2-16x+80 α,β,Δ are 4,-4,5
@skb
Given 2 of its roots are equal but of opposite signs
Let α,β be equal roots
such that β = -α
From this polynomial,
Sum of the roots ⇒ α+β+Δ = -coefficient of x²/ coefficient of x³
⇒ α-α+Δ = -(-5)/1
Δ = 5 --------- One of the root (1)
Product of roots ⇒ αβΔ = -constant/coefficient of x³
⇒ α(-α)Δ = -80/1
⇒ -α²Δ = -80
⇒ α²Δ = 80
From(1), Substituting Δ=5
⇒ α²×5 = 80
⇒ α² = 80/5
⇒ α² = 16
⇒ α = √16 = +-4
⇒ α = +4 or -4 {where -4 = -α = β}
Therefore, the three roots of given polynomial x3-5x2-16x+80 α,β,Δ are 4,-4,5
@skb
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