Question

i want the full process please do it​

Answer 1

Answer:-

Given :

p^2(q-r)-q(r-q)

To find:

Factorise p^2(q-r)-q(r-q) ?

Solution:

Given expression is p^2(q-r)-q(r-q)

It can be written as

=> p^2(q)-p^2(r) -q(r) -q(-q)

=> p^2q-p^2r -qr +q^2

It can be arranged as

=>(p^2q+q^2) - (p^2r+qr)

=> q (p^2 +q) -r (p^2+q)

=> (p^2 + q) (q-r)

p^2(q-r)-q(r-q) = (p^2 + q) (q-r)

Answer:

The factorization of the given expression p^2(q-r)-q(r-q) is (p^2 + q) (q-r)

Used Concept:

Arranging the given terms by Commutative property.

• Expressing the given expression as the product of factors is called factorization and expressing as the product of prime factors is called Prime factorization.

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Hope It Helps You! :)

Regards,

Rishita R Shrivastava