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x+5/x = x+2/x-2
cross multiplying
(x-2)(x+5) = (x)(x+2)
x^2+3x-10 = x^2+2x
cut x^2 from both the sides
3x-10=2x
3x-2x = 10
thus x= 10
BC=15
AB=10
CD=12
AD=8
cross multiplying
(x-2)(x+5) = (x)(x+2)
x^2+3x-10 = x^2+2x
cut x^2 from both the sides
3x-10=2x
3x-2x = 10
thus x= 10
BC=15
AB=10
CD=12
AD=8
schoolboysatyam:
thanks
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