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ujwal10:
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HI !
LHS = tan⁴A+tan²A
taking common ,
= tan²A(tan²A+1)
we know that , 1 + tan²A = sec²A , and sec²A -1 = tan²A
= tan²A(sec²A)
= (sec²A-1)sec²A
= sec⁴A-sec²A
= RHS
LHS = tan⁴A+tan²A
taking common ,
= tan²A(tan²A+1)
we know that , 1 + tan²A = sec²A , and sec²A -1 = tan²A
= tan²A(sec²A)
= (sec²A-1)sec²A
= sec⁴A-sec²A
= RHS
★Perfect★
hmmm
^^
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