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Let ABCD is square of side length 0.2m and four equal point charge each of 16 micro coulomb are placed on the four corner A, B, C and D of the square.
- force exerted by B on A = Kq²/a² ,where q = 16 microcoulomb, a = 0.2m
- force exerted by C on A = Kq²/(√2a)² = Kq²/2a²
- force exerted by D on A = Kq²/a²
- resultant of force exerted by B and D on A = √{(Kq²/a²)² + (Kq²/a²)²}= √2Kq²/a² , it is along CA .
- net force experienced by A = resultant of force exerted by B and D on A + force exerted by C on A
= √2Kq²/a² + Kq²/2a²
= (√2 + 1/2)Kq²/a²
= (2√2 + 1)Kq²/2a²
Put
- k = 9 × 10⁹ Nm²/C²
- q = 16 × 10^-6 C
- a = 0.2 m
= (2√2 + 1) × 9 × 10^9 × (16 × 10^-16)²/2(0.2)²
= (2√2 + 1) × 9 × 256 × 10^-3/(0.08)
= (2√2 + 1) × 9 × 32 × 10^-1
= 110.258 N along CA
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