Question

I want the solution to this question.

Answer 1

radius is ≈ 6.04 cm
use Pythagoras theorem twice then equate

Answer 2

The line from O to P is perpendicular bisector of AB and CD.
So,
BP=5/2
DQ=11/2
OB=OD= radius of same circle (1)
And taking OQ=x
Using pythagoras theorem,
BP sq.+OP sq.=OB sq. (2)
QD sq.+OQ sq.=OD sq. (3)
From 1, 2 and 3
BP sq.+OP sq.=QD sq.+OQ sq.
5/2 sq.+(3+x) sq.=11/2 sq. +x sq.
25/4+9+6x+x sq.=121/4+x sq. [x sq. gets cancelled]
6x=[(121-25)/4]-9
x=(96/4)-9
x=24-9
x=15 cm
Applying this value in equation 3 we get,
OD sq.=11/2 sq.+15 sq.
=(121/4)+225
=(121+900)/4
=1021/4
OD=root 1021/4 [ root of 1021 approx. 32]
=32/2
=16 cm
So, the radius of the circle is 16 cm. Hope this will help!! Please mark as brainliest!