Math, asked by newhelp, 9 months ago

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Answered by Priyanshu1singh
0

Answer:

0

Step-by-step explanation:

By rationalising all terms and eleminating the denominator all the terms get canceled up

Answered by nonobhai
1

Answer:

26+6+362−6+383=8−26−22

Step-by-step explanation:

we have to simplify \frac{2\sqrt{6}}{\sqrt{2}+\sqrt{3}}+\frac{6\sqrt{2}}{\sqrt{6}+\sqrt{3}}-\frac{8\sqrt{3}}{\sqrt{6}+\sqrt{3}}2+326+6+362−6+383

we simplify by rationalizing the denominator of each term.

\implies\frac{2\sqrt{6}}{\sqrt{2}+\sqrt{3}}\times\frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}}+\frac{6\sqrt{2}}{\sqrt{6}+\sqrt{3}}\times\frac{\sqrt{6}-\sqrt{3}}{\sqrt{6}-\sqrt{3}}-\frac{8\sqrt{3}}{\sqrt{6}+\sqrt{3}}\times\frac{\sqrt{6}-\sqrt{3}}{\sqrt{6}-\sqrt{3}}⟹2+326×2−32−3+6+362×6−36−3−6+383×6−36−3

\implies\frac{4\sqrt{3}-6\sqrt{2}}{2-3}+\frac{12\sqrt{3}-6\sqrt{6}}{6-3}-\frac{24\sqrt{2}-24}{6-3}⟹2−343−62+6−3123−66−6−3242−24

\implies\frac{4\sqrt{3}-6\sqrt{2}}{-1}+\frac{12\sqrt{3}-6\sqrt{6}}{3}-\frac{24\sqrt{2}-24}{3}⟹−143

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