Question

I want to ask maths questions of factorisation 1-2ab-(a² +b²)

Answer 1

Consider, (1 – a2 – b2 – 2ab)
= [1 – (a2 + b2 + 2ab)]
= [12 – (a + b)2]
= [1 – (a + b)] [1 + (a + b)]
= [1 – a – b] [1 + a + b]

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Answer 2

$\bold{Answer :}$

Now,

1 - 2ab - (a² + b²)

= 1 - (2ab + a² + b²)

= 1 - (a² + 2ab + b²)

= 1² - (a + b)²

= {1 + (a + b)} {1 - (a + b)}

= (1 + a + b) (1 - a - b),

which is the required factorization.

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