I want to ask this question
Answers
Answer:
53rd term is the answer.
EXPLANATION IS IN THE PHOTO.
LOOK AT IT CAREFULLY OR YOU WILL NOT UNDERSTAND :)
Given :-
The AP is 8,14,20,26,...
To find :-
The term of the AP will be 72 more than ist 41st term.
Solution :-
Given Arithmetic Progression is 8,14,20,26,...
First term (a) = 8
Common difference (d) = 14-8 = 6
We know that
The nth term of an AP is an = a+(n-1)d
41st term = 8+(41-1)(6)
=> 41st term = 8+(40×6)
=> 41st term = 8+240
=> 41st term = 248
Let the term which 72 more than 41st term of the AP be an
Therefore an = 41st term + 72
=> a+(n-1)d = 248+72
=> 8+(n-1)(6) = 320
=> 8+6n-6 = 320
=> 6n+2 = 320
=> 6n = 320-2
=> 6n = 318
=> n = 318/6
=> n = 53
The required term = 53rd term
Answer :-
53rd term of the AP is 72 more than its 41st term.
Check :-
We have,
a = 8
d = 6
41st term = 248
Now,
53rd term = 8+(53-1)(6)
=> 53rd term = 8+(52×6)
=> 53rd term = 8+312
=> 53rd term = 320
=> 53rd term = 248+72
=> 53rd term = 41st term +72
Verified the given relations in the given problem.
Used formulae:-
♦ The nth term of an AP is an = a+(n-1)d
- an = nth term
- a = first term
- d = common difference
- n = no. of terms