i want to factorize 63a²b²-7
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Answered by
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63a^2b^2-7
=7 [9a^2b^2-1]
=7 (3ab-1)(3ab+1)
=7 [9a^2b^2-1]
=7 (3ab-1)(3ab+1)
Answered by
1
Answer:
63a²b²-7
Step-by-step explanation:
= a²-b²=(a-b) (a+b)
= 63= 7×3×3
=7=7×1
therefore 7(3ab-1)3ab+1
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