Question

I want to know the Answer

Answer 1

$\frac{1}{ \sqrt{4} + \sqrt{5} } + \frac{1}{ \sqrt{5} + \sqrt{6} } + \frac{1}{ \sqrt{6} + \sqrt{7} } + \frac{1}{ \sqrt{7} + \sqrt{5} } + \frac{1}{ \sqrt{8} + \sqrt{9} } = 1$

$\frac{ \sqrt{4} - \sqrt{5} }{4 - 5} + \frac{ \sqrt{5} - \sqrt{6} }{5 - 6} + \frac{ \sqrt{6} - \sqrt{7} }{6 - 7} + \frac{ \sqrt{7} - \sqrt{8} }{7 - 8} + \frac{ \sqrt{8} - \sqrt{9} }{8 - 9} = 1$

$\frac{ \sqrt{4} - \sqrt{5} }{ - 1} + \frac{ \sqrt{5} - \sqrt{6} }{ - 1} + \frac{ \sqrt{6} - \sqrt{7} }{ - 1} + \frac{ \sqrt{7} - \sqrt{8} }{ - 1} + \frac{ \sqrt{8} - \sqrt{9} }{ - 1} = 1$

$- \sqrt{4} + \sqrt{5} - \sqrt{5} + \sqrt{6} - \sqrt{6} + \sqrt{7} - \sqrt{7} + \sqrt{8} - \sqrt{8} + \sqrt{9} = 1$

$- \sqrt{4} + \sqrt{9} = 1$

$- 2 + 3 = 1$

$1 = 1$

Hence, Proved.

❤ғȏʟʟȏẇ ṃє❤