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(i) since AB=AC (given), ABC=ACB(base angle isos. triangle)
ABC=(180-36)/2=72(angle sum of triangle)
(ii) ACB=ABC=72(proved)
(iii) ABD=180-72=108(adj. angle on st. line)
DAB=180-45-108=27(angle sum of triangle)
(iv) EAC=180-45-40-36-27=32(angle sum of triangle)
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