I want to know the answer of questions 3,4,5 someone can help ,
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now answer no.5 is
Both pistons P1 and P2 are hydraulically coupled. Hence,
according to the Pascal's law, the pressure exerted to the working fluid must be equal for both pistons.
Pressure = Force / Area
P = F/A
As per question,
P1 = F1/A1 (for piston 1)
P2 = F2/A2 (for piston 2)
Since, P1 = P2
F2 = (F1/A1) * A2
A2/A1 = [pi*{(50^2)/4}] ÷ [pi*{(10^2)/4}] = 25
F2 = F1 * 25 = 25 N
I hope it helps.
PLEASE MARK THIS AS BRAINLIEST...
Both pistons P1 and P2 are hydraulically coupled. Hence,
according to the Pascal's law, the pressure exerted to the working fluid must be equal for both pistons.
Pressure = Force / Area
P = F/A
As per question,
P1 = F1/A1 (for piston 1)
P2 = F2/A2 (for piston 2)
Since, P1 = P2
F2 = (F1/A1) * A2
A2/A1 = [pi*{(50^2)/4}] ÷ [pi*{(10^2)/4}] = 25
F2 = F1 * 25 = 25 N
I hope it helps.
PLEASE MARK THIS AS BRAINLIEST...
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