I want to know the solution of the question
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At the highest point the velocity of the ball becomes 0.
As K.E.=1/2mv^2, the kinetic energy at the highest point becomes 0.
As K.E.=1/2mv^2, the kinetic energy at the highest point becomes 0.
Sidhatrth:
then what is the need of angle in the question
It is just there to confuse you.
what is the need of angle.. please tell me
Ok I'm Sorry for the wrong answer.
The correct answer would be 93.89J or approximately 94J.
draw the diagram on a paper. Look the vertical velocity of the ball always becomes 0m/s at the highest point (at whatever angle it is thrown) but there is a horizontal velocity. Look at the horizontal component which is u cos@(@is angle). Now calculate the K.E.=1/2mv^2, where m=200g=0.2kg and v=u cos@.
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