Question

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Answer 1

Answer:

In the given compound,

There is 2 sp³ , 2 sp² and 3 sp hybridized carbon atom.

Hence, number of sp³ hybrid orbitals = 4+4,

no. of sp² hybrid orbitals = 3+3,

no. of sp hybrid orbitals = 2+2+2 .

Hence ratio of sp : sp² : sp³ = 6:6:8 = 3:3:4

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