Question

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Answer 1

Answer:

Atomic number of Sodium(Na) atom is 11. 

Electronic configuration is : 

Na = 2, 8, 1 

So it contains 1 valence electron. In order to achieve the nearest noble gas configuration, it loses one electron to form Sodium ion. 

Na+=2,8 

Atomic number of Chlorine(Cl) atom is 17. 

Electronic configuration is : 

Cl = 2, 8, 7 

So it contains 7 valence electron. In order to achieve the nearest noble gas configuration, it gains one electron to form Chloride ion. 

Cl−=2,8,8

  

An Ionic bond is formed between sodium ion and chloride ion by complete transfer of electron from sodium to chlorine. 

Explanation:

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Answer 2

Answer:

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Explanation:

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