I want
x cube minus 3 X square + X - 3
Answers
Step-by-step explanation:
1
Secondary School Math 5 points
Using factor theorem factorise x cube -3x square -x plus 3
Ask for details Follow Report by Shankarreddy15 17.09.2017
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EkuEkta
EkuEkta Ambitious
X^3-3x^2-x+3=x^2(x-3)-1(x-3)=(x-3) (x^2-1)
hope this will help u
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pinquancaro Virtuoso
Answer:
The factor of the equation is x^3-3x^2-x+3=(x-3)(x-1)(x+1)
Step-by-step explanation:
Given : Equation x^3-3x^2-x+3
To find : Using factor theorem factorise equation?
Solution :
Factor theorem is the remainder theorem in which taking common factor from the equation and then divide from the quotient or factories it again.
We try to factor the common from the equation,
x^3-3x^2-x+3
=x^2(x-3)-1(x-3)
The common factor is (x-3),
=(x-3)(x^2-1)
Now, again we factor x^2-1=(x-1)(x+1)
Substitute,=(x-3)(x-1)(x+1)
Therefore, The factor of the equation is x^3-3x^2-x+3=(x-3)(x-1)(x+1)