Question

i) Water is filled in a right cylindrical tank with base radius 14 cm, such that water
level is 3 cm below the top. When an iron ball is dropped in the tank, 3003 cm of
water flows out. Find the radius of the ball.​

Answer 1

Answer:

Step-by-step explanation:

HIII XD

Reading the question very carefully

We can understand that

Volume of the iron Ball = Volume of water displaced by the Ball

thus

if the radius of ball is r

then Volume of the spherical ball = 4/3 pi r^3

                       Thus

                                     4/3 pi r^3 = 3003

                                      pi r^3 = 9009/4

                                          r^3 = 9009/4 * 3.14

                                             r = 41.35 Cm

thus radius of ball is 41.35 Cm

BRAINLIEST PLS