Question

(i) What is the difference in potential between two points, one at 10 cm, and the other at 20 cm from a charge
of -5.5 uC ?​

Answer 1

Answer:

Let x be the distance from 10μc where potential is zero

Let x be the distance from 10μc where potential is zero⇒0= xk(10μC) + 20−x

Let x be the distance from 10μc where potential is zero⇒0= xk(10μC) + 20−x k(−20μC)

Let x be the distance from 10μc where potential is zero⇒0= xk(10μC) + 20−x k(−20μC)⇒0= x10 − 20−x20

Let x be the distance from 10μc where potential is zero⇒0= xk(10μC) + 20−x k(−20μC)⇒0= x10 − 20−x20⇒(20−x)10=20x

Let x be the distance from 10μc where potential is zero⇒0= xk(10μC) + 20−x k(−20μC)⇒0= x10 − 20−x20⇒(20−x)10=20x⇒20=3x

Let x be the distance from 10μc where potential is zero⇒0= xk(10μC) + 20−x k(−20μC)⇒0= x10 − 20−x20⇒(20−x)10=20x⇒20=3x ⇒x= 320 =6⋅67cm