Question

(i) What is the share of A in the original sum of money?

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Answer 1

see in attachment mate ✌️

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$✴lets \: share \: of \: A \: is \: rs.x$$✳then \: share \: of \: (69300 - x)$$age \: of \: A \: is \: 21yrs$

$So, time \: of \: investment \: of \: A \: is \: = (24 - 21) = 3yrs$

$and \: time \: of \: investment \: of \: B \: is = (24 - 22) = 2yrs$

$Rate = 10\%$

$amt \: of \: A \: after \: 3yrs = x(1 + \frac{10}{100} {)}^{3}$

$amt \: of \: B \: after \: 2yrs = (69300 - x)(1 + \frac{10}{100} {)}^{2}$

$amt \: of \: A = amt \: of \: B$$so, \: x(1 + \frac{10}{100} {)}^{3} = (69300 - )(1 + \frac{10}{100} {)}^{2}$$so, \: x(1 + \frac{10}{100}) = (69300 - x)$

$11x + 10x = 693000$

$21x = 693000$

$x = \cancel\frac{693000}{33000}$

$x = 33000$

$\boxed{share \: of \: A = 33000}$$\small {\boxed{share \: of \: B = 693000 - 33000 = 36300}}$

Answer 2

Step-by-step explanation:

Lets share of A is Rs X

Then share of =(69300- x)

Age of A is 21 year

So time of investment of A is (24-21)=3 year

And time of investment of B is (24-22)=2 year

Rate =10%

Amt of A after 3 years =X(1+ 10010 ) 3

Amt of B after 2 years=(69300−X)(1+ 10010 ) 2Amt of A= Amt of B

soX(1+ 10010) 3 =(69300−)(1+ 10010 ) 2

SoX(1+ 10010 )= (69300-X)

11X+10X=693000

X= 33000

share of A = 33000

share of B= 69300-33000=36300