(i)what is wawelength of Hb line in balmer series of H spectrum
(ii)When e are de exciting from nth orbit to ground level of H atom of 15 spectral lines are formed during shortest wawelength among them is
(iii)The radii of 2 of first 4 orbits of H atom are in ratio 1:4,the energy diference may be
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use formula of rz^2*i/n^2-!/n^2
ramanason:
thnks
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