Question

(i) What number should be subtracted from
$\frac{ -3}{ 5} \: to \: get \: \frac{9}{11}$


​

Answer 1

Step-by-step explanation:

$let \: \: the \: \: no. \: subtracted \: from \: \frac{ - 3}{5} \: be \: x$

$= > x - \frac{3}{5} = \frac{9}{11}$

$= > x = \frac{9}{11} + \frac{3}{5}$

$= > x = \frac{45 + 33}{55}$

$= > x = \frac{78}{55}$

verification:

$= > \frac{78}{55} - \frac{3}{5} = \frac{9}{11}$

$= > \frac{78 - 33 }{55} = \frac{9}{11}$

$= > \frac{45}{55} = \frac{9}{11}$

$= > \frac{9}{11} = \frac{9}{11}$

Answer 2

Answer:

Step-by-step explanation:

let \: \: the \: \: no. \: subtracted \: from \: \frac{ - 3}{5} \: be \: xlettheno.subtractedfrom

5

−3

bex

= > x - \frac{3}{5} = \frac{9}{11}=>x−

5

3

=

11

9

= > x = \frac{9}{11} + \frac{3}{5}=>x=

11

9

+

5

3

= > x = \frac{45 + 33}{55}=>x=

55

45+33

= > x = \frac{78}{55}=>x=

55

78

verification:

= > \frac{78}{55} - \frac{3}{5} = \frac{9}{11}=>

55

78

−

5

3

=

11

9

= > \frac{78 - 33 }{55} = \frac{9}{11}=>

55

78−33

=

11

9

= > \frac{45}{55} = \frac{9}{11}=>

55

45

=

11

9

= > \frac{9}{11} = \frac{9}{11}=>

11

9

=

11

9