Question

i) What will be pressure exerted by a mixture of 3.2 gm of methane and 4.4 g of carbon dioxide

contained in a 9dm3 flask of 270C?​

Answer 1

Answer:

Let's apply ldeal gas law: PV =nRT

T = 300°K.

V = 9 dm³ = 9 × 10^-3 m³ or 9L

Molecular mass of Methane: CH4 =16. of Carbon Dioxide CO2 = 44.

Total Number of moles of the gases in the

mixture:

n=n1+n2

=3.2/16 + 4.4/44

= 0.3 mol

R = 8.318 J/°K

P = nRT/V

= 0.3 molx 8.314 J/K/mol x 300°K /

O.009m³

P = 0.8314 bar or 8.314×10^4Pa or 0.83 atmn

We can also calculate the partial pressure exerted by Methane and

Carbon Dloxide individually..

P1 = n1/(n1+n2) *P

P2 = n2/(n1+n2) *P