Question

i) When the object is placed at a distance of 80cm in front of the lens it forms a real
and diminished image at a distance of 48 cm from the lens. If the object distance
and image distance are interchanged a magnified image is formed. Then power of
the lens is equal to
8 .2.10​

Answer 1

Answer:

Power is simply =v / u

Here v= 48 cm

u=80m

P = 48 / 80 = 0. 6

if we want distance interchanged then Power wiIl be

P = 80 / 48 = 1. 66

Step-by-step explanation:

Power = distance of image / distance of object