Question

I. Which of the following has the largest
number of atoms?
a. 1g Au (s) b.1g Na(s)
c. 1g Li (s) d. 1g C1, (9)​

Answer 1

(i) 1 g Au = 1/197 mol = 1/197×6.022×1023 atoms

(ii) 1 g Na = 1/23 mol = 1/23×6.022×1023 atoms

(iii) 1 g Li = 1/7 mol = 1/7×6.022×1023 atoms

(iv) 1 g Cl2 = 1/71 mol = 1/71×6.022×1023 atoms

Thus, 1 g of Li has the largest number of atoms.

Answer 2

Explanation:

(i) 1 g Au = 1/197 mol = 1/197×6.022×1023 atoms

(ii) 1 g Na = 1/23 mol = 1/23×6.022×1023 atoms

(iii) 1 g Li = 1/7 mol = 1/7×6.022×1023 atoms

(iv) 1 g Cl2 = 1/71 mol = 1/71×6.022×1023 atoms

Thus, 1 g of Li has the largest number of atoms.

Hope it helps you ..