Question

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evaluate 8x³-27y³​

Answer 1

• 8x³ - 27y³

=> (2x)^3 - (3y)³

By using identinty:- a³ - b³= (a-b)( a²+ab+b²)

=> (2x - 3y)[(2x)² + (2x)(3y) + (3y)²]

=> (2x - 3y)(4x² + 6xy + 9y²)

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Answer 2

Step-by-step explanation:

${8x}^{3} - {27y}^{3}$

${(2x)}^{3} - {(3y)}^{3}$

${x}^{3} - {y}^{3} = (x + y)( {x}^{2} - 2xy + {y}^{2} )$