Question

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.Find the value of K if( x-1)is a factor ofp(x)=k x²-√2x +1


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Answer 1

$\huge\mathfrak\red{Answer:}$

Factor:

• A number or algebric expression which can divide other number or algebric expression completely
• For ex : 2 is factor of 4

Given:

• A Quadratic Polynomial whose one of its factor is ( x - 1 )
• $p(x) = k {x}^{2} - \sqrt{2} x + 1$

To Find:

• The value of k in the following given expression

Solution:

Since ( x - 1 ) is a factor of P( x )

Hence

X - 1 = 0 must be a zero

X = 1

Hence X = 1 is a zero of P( x )

Putting x = 1 in the given equation

$p(1) = k{(1)}^{2} - \sqrt{2} + 1$

$k - \sqrt{2} + 1 = 0$

$k = \sqrt{2} - 1$

Hence value of k comes to be

$\sqrt{2} - 1$

Answer 2

Answer:

Hey mate here is your answer

Step-by-step explanation:

by solving the equation the value of k comes out to be root 2-1

Hope it help

Plss pray for my sis she had a surgery today