Question

I will follow you...if you answer this​

Answer 1

Please find the attachment ..

solved

Answer 2

If alpha beta gamma are the zeros of the polynomial $f(x)=ax^3+bx^2+cx+d.$

Then ,

$\alpha +\beta+\gamma =-b/a$

$\alpha \beta +\beta \gamma+\gamma\alpha =c/a$

$\alpha \beta \gamma=-d/a$

Now ,

$\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma} =\frac{\alpha\beta +\beta\gamma+\gamma\alpha }{\alpha\beta\gamma}$

$\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma} =\frac{c/a}{-d/a}$

$\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma} =-c/d$