Question

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Answer 1

Explanation:

Torque about a point = Total force × perpendicular distance from the point to that force. Let anticlockwise torque = + ve And clockwise acting torque = –ve Force acting at the point B is 15 N Therefore torque at O due to this force = 15 × 6 × 10–2 × sin 37° = 15 × 6 × 10–2 × 3/5 = 0.54 N-m (anticlock wise) Force acting at the point C is 10 N Therefore, torque at O due to this force = 10 × 4 × 10–2 = 0.4 N-m (clockwise) Force acting at the point A is 20 N Therefore, Torque at O due to this force = 20 × 4 × 10–2 × sin30° = 20 × 4 × 10–2 × 1/2 = 0.4 N-m (anticlockwise) Therefore resultant torque acting at ‘O’ = 0.54 – 0.4 + 0.4 = 0.54 N-m.Read more on Sarthaks.com - https://www.sarthaks.com/41887/calculate-the-total-torque-acting-on-the-body-shown-in-figure-10-e2-about-the-point-0

Answer 2

answer in attachment

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