I will give Brainiest, for this question , Qu. 8 or 9
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A8)
Volume of sphere = 4/3 πr³
Find the volume:
Volume of the sphere = 4/3 π (9)³
Volume of the sphere = 972π cm³
Find the radius:
Radius = Diameter ÷ 2
Radius = 4 ÷ 2
Radius = 2mm = 0.2 cm
Find the length of the wire:
πr²h = Volume
π(0.2)² h = 972π
0.04πh = 972π
h = 972π ÷ 0.04π
h = 24300 cm
Answer: The length of the wire is 24300 cm
A9)
It is given that ,
Area of the sector ( A ) = 15π sq cm
Radius of the circle ( r ) = 6 cm
We know that ,
1 ) Area of the sector ( A ) = ( x°/360 ) × πr²
Where , x is sector angle ,
2 ) length of the arc ( l ) = ( x°/360 ) × 2πr
Now ,
1 ) ( x°/360 ) × πr² = A
( x°/360 ) × π × 6² = 15π
x° = ( 15π × 360 )/( π × 36 )
x° = 150
2 ) length of the arc ( l ) = ( x/360 ) × 2πr
l = ( 150/360 ) × 2 × π × 6
l = 5π cm
hope this helps you
Volume of sphere = 4/3 πr³
Find the volume:
Volume of the sphere = 4/3 π (9)³
Volume of the sphere = 972π cm³
Find the radius:
Radius = Diameter ÷ 2
Radius = 4 ÷ 2
Radius = 2mm = 0.2 cm
Find the length of the wire:
πr²h = Volume
π(0.2)² h = 972π
0.04πh = 972π
h = 972π ÷ 0.04π
h = 24300 cm
Answer: The length of the wire is 24300 cm
A9)
It is given that ,
Area of the sector ( A ) = 15π sq cm
Radius of the circle ( r ) = 6 cm
We know that ,
1 ) Area of the sector ( A ) = ( x°/360 ) × πr²
Where , x is sector angle ,
2 ) length of the arc ( l ) = ( x°/360 ) × 2πr
Now ,
1 ) ( x°/360 ) × πr² = A
( x°/360 ) × π × 6² = 15π
x° = ( 15π × 360 )/( π × 36 )
x° = 150
2 ) length of the arc ( l ) = ( x/360 ) × 2πr
l = ( 150/360 ) × 2 × π × 6
l = 5π cm
hope this helps you
bhushan79:
In qu. no . 8, hight is 108 m
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