Math, asked by tiegenthompson, 1 year ago

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Use the given information to complete parts I and II. In your final answer, include all calculations. Planet Earth has an approximate diameter of 1.2742 · 10 10 millimeters. The sun has a diameter of 1.391 · 10 6 kilometers.

Part I: Given that for every one kilometer there are 1,000,000 millimeters, which unit of measurement should be used to best represent the lengths of the sun and Earth's diameters?

Part II: Approximate how many times greater the sun's diameter is than planet Earth's.

Answers

Answered by meenu977
3

Answer:

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Attachments:
Answered by sk940178
7

Answer:

Part I: Use Kilometer unit.

Part II: 109 times.

Step-by-step explanation:

Part I: The approximate diameter of Planet Earth is 1.2742×10^{10} millimeters.

Now, 1 Kilometer = 1000000 millimeters

So, the approximate diameter of Earth in Km. will be \frac{1.2742*10^{10} }{10^{6} } Km.=1.2742*10^{4} Km. ......... (1)

And, the Sun has a diameter of 1.391*10^{6} Km. ...... (2)

Therefore, it will be best to represent those diameters in Kilometer unit. (Answer)

Part II: If we divide the diameter of Sun with the diameter of Earth then we will get \frac{1.391*10^{6} }{1.2742*10^{4} } =109.166.

Hence, approximately 109 times greater the Sun's diameter than Planet Earth's diameter. (Answer)

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