Math, asked by ushathakur34639, 11 months ago

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How many digits in the square root of a perfect square number having n digits, whose n is an odd number. Also, find the number of digits in square root 1522756

Answers

Answered by Terry1987
4

Answer:

The square root of a number having n digits will have (n+1)/2 digits. For the given number, the square root will have (7+1)/2 digits, or 4 digits.

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